Explain the formation of alcohol from alkene via acid-catalyzed hydration.

(N/A) The acid-catalyzed hydration of alkenes involves the addition of water $(H_{2}O)$ across the double bond in the presence of an acid catalyst like $H_{2}SO_{4}$.
The mechanism proceeds as follows:
$1$. Protonation of the alkene to form a carbocation intermediate.
$2$. Nucleophilic attack by water on the carbocation.
$3$. Deprotonation to yield the alcohol.
This reaction follows the Markovnikov rule,where the hydroxyl group $(-OH)$ attaches to the more substituted carbon atom. The general reaction is:
$R-CH=CH_{2} + H_{2}O \xrightarrow{H^{+}} R-CH(OH)-CH_{3}$